McGraw Hill Glencoe Algebra 2, 2012
MH
McGraw Hill Glencoe Algebra 2, 2012 View details
Mid-Chapter Quiz
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Exercise 13 Page 91

Substitute 0 and solve for a variable twice before graphing.

x-intercept: (10,0)
y-intercept: (0,5)

Practice makes perfect

We will find the x- and y-intercepts first. Then by plotting them and connecting with a line, we will graph the given equation.

Finding the x-intercept

Think of the point where the graph of an equation crosses the x-axis. The y-value of that ( x, y) coordinate pair is 0 and the x-value is the x-intercept. To find the x-intercept of the given equation, we will substitute 0 for y and solve for x.

10-x=2y
10-x=2( 0)
10-x=0
- x=- 10
x=10
An x-intercept of 10 means that the graph passes through the x-axis at the point ( 10,0).

Finding the y-intercept

Let's use the same concept to find the y-intercept. Consider the point where the graph of the equation crosses the y-axis. The x-value of the ( x, y) coordinate pair at the y-intercept is 0. Therefore, substituting 0 for x will give us the y-intercept.

10-x=2y
10-( 0)=2y
10=2y
5=y

A y-intercept of 5 means that the graph passes through the y-axis at the point (0, 5).

Graphing the Equation

We can now graph the equation by plotting the intercepts and connecting them with a line.