McGraw Hill Glencoe Algebra 2, 2012
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McGraw Hill Glencoe Algebra 2, 2012 View details
2. Verifying Trigonometric Identities
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Exercise 58 Page 884

Start with substituting 12tanθ for x and simplifying. Then use Trigonometric Identities to transform the function.

f(θ)=1/2sinθ

Practice makes perfect
We are given a function and want to write it in terms of a single trigonometric function of θ. Let's start by substituting 12tanθ for x. Here θ is greater than - π2 and less than π2.
x/sqrt(1+4x^2)
12tanθ/sqrt(1+4( 12tanθ)^2)
Simplify right-hand side
12tanθ/sqrt(1+4( 12)^2(tanθ)^2)
12tanθ/sqrt(1+4( 14)(tanθ)^2)
12tanθ/sqrt(1+(1)(tanθ)^2)
12tanθ/sqrt(1+(tanθ)^2)

(tan(θ))^2=tan^2(θ)

12tanθ/sqrt(1+tan^2θ)
We will now use the trigonometric identities to transform the function. First, consider the denominator. Recall one of the Pythagorean Identities. tan^2θ+1=sec^2θ

Let's use this to transform our function. f(θ)=12tanθ/sqrt(1+tan^2θ)=12tanθ/sqrt(sec^2θ) We know that sqrt(x^2)=|x|. To determine if secθ is positive or negative we need to consider the possible values of θ. Since - π2<θ< π2, θ lies in Quadrant I or Quadrant IV. Recall the behavior of secant in each quadrant.

In Quadrant I and IV the value of secant is positive, so sqrt(sec^2θ)=secθ. f(θ)=12tanθ/sqrt(sec^2θ)=12tanθ/secθ Now recall the definition of secant and one of the Quotient Identities considering tangent. secθ = & 1/cosθ tanθ = & sinθ/cosθ Finally, we will use both of these identities to transform our function.
f(θ)=12tanθ/secθ
f(θ)=12* sinθcosθ/1cosθ
Simplify right-hand side
f(θ)=1/2 * sinθcosθ/1cosθ
f(θ)=1/2 * sinθ/cosθ*cosθ/1
f(θ)=1/2* sinθcosθ/cosθ
f(θ)=1/2sinθ
We have obtained a function only in terms of sine of θ, so this is the end of our task.