McGraw Hill Glencoe Algebra 2, 2012
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McGraw Hill Glencoe Algebra 2, 2012 View details
1. Trigonometric Functions in Right Triangles
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Exercise 48 Page 797

Practice makes perfect
a We are given two bicycle ramps as shown.

We want to find how much taller the second ramp is than the first. From the graphs we can see that the mentioned lengths correspond to the opposite sides of the given angles. Let's name the desired sides h_1 and h_2.

We will write equations that include the ratio of the opposite sides and the adjacent sides of the given angles. Therefore, we will use the tangent of an acute angle θ, which is the ratio between the lengths of the opposite side and the adjacent side. tan θ = Opposite/Adjacent [1em] ⇓ [0.5em] tan 20^(∘) = h_1 8 and tan 35^(∘) = h_2 8 Now we will solve the equations one by one. Let's begin by solving h_1.

tan 20^(∘) = h_1/8
tan 20^(∘)(8) = h_1
h_1 = 2.91176...
h_1 ≈ 2.9

We found that the height of the first ramp is about 2.9 feet. From here, we will find h_2.

tan 35^(∘) = h_2/8
tan 35^(∘)(8) = h_2
h_2 = 5.60166...
h_2 ≈ 5.6

The height of the second ramp is approximately 5.6 feet. We want to find how much taller h_2 is than h_1. h_2- h_1&= 5.6- 2.9 &=2.7 feet Therefore, the second ramp is about 2.7 feet taller than the first one.

b Now we want to find how much longer the second ramp is than the first.

From the graphs we can see that the desired lengths correspond to the hypotenuses. Let's name the hypotenuses x_1 and x_2.

We will write equations that include the ratio of the adjacent sides and the hypotenuses of the given angles. Therefore, we will use the cosine of an acute angle θ, which is the ratio between the lengths of the adjacent side and the hypotenuse. cos θ = Adjacent/Hypotenuse [1em] ⇓ [0.5em] cos 20^(∘) = 8 x_1 and cos 35^(∘) = 8 x_2 Now we will solve the equations one by one. Let's begin by solving x_1.

cos 20^(∘) = 8/x_1
cos 20^(∘)(x_1) = 8
x_1 = 8/cos 20^(∘)
x_1 = 8.51342...
x_1 ≈ 8.5

We found that the length of the first ramp is about 8.5 feet. From here we will find x_2.

cos 35^(∘) = 8/x_2
cos 35^(∘)(x_2) = 8
x_2 = 8/cos 35^(∘)
x_2 = 9.76619...
x_2 ≈ 9.8

The length of the second ramp is approximately 9.8 feet. We want to find how much longer x_2 is than x_1. x_2- x_1&= 9.8- 8.5 &=1.3 feet Therefore, the second ramp is about 1.3 feet longer than the first one.