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Identify the hypotenuse as well as the adjacent and opposite sides of the angle. Use the Pythagorean Theorem if a side length is missing.
sin θ=2sqrt(13)/13, cos θ=3sqrt(13)/13, tan θ=2/3, csc θ=sqrt(13)/2, sec θ=sqrt(13)/3, cot θ=3/2
In a right triangle the hypotenuse is the side that is opposite the right angle. If we take one of the acute angles as a reference, we can identify the opposite and adjacent sides to the angle.
In the given right triangle we have the opposite and the adjacent side. However, we are missing the hypotenuse.
To find the length of the hypotenuse we will substitute a= 6 and b= 9 into the Pythagorean Theorem and solve for c.
a= 6, b= 9
Calculate power
Add terms
Rearrange equation
sqrt(LHS)=sqrt(RHS)
Split into factors
sqrt(a* b)=sqrt(a)*sqrt(b)
Note that when solving the equation we only kept the principal root. This is because c is the side length of a triangle and must be positive.
Let's find the values of the six trigonometric functions for angle θ. Remember to rationalize denominators if needed.
| Function | Substitute | Simplify |
|---|---|---|
| sin θ=opp/hyp | sin θ=6/3sqrt(13) | sin θ=2sqrt(13)/13 |
| cos θ=adj/hyp | cos θ=9/3sqrt(13) | cos θ=3sqrt(13)/13 |
| tan θ=opp/adj | tan θ=6/9 | tan θ=2/3 |
| csc θ=hyp/opp | csc θ=3sqrt(13)/6 | csc θ=sqrt(13)/2 |
| sec θ=hyp/adj | sec θ=3sqrt(13)/9 | sec θ=sqrt(13)/3 |
| cot θ=adj/opp | cot θ=9/6 | cot θ=3/2 |
a/b=.a /3./.b /3.
a/b=a * sqrt(13)/b * sqrt(13)
a* a=a^2
( sqrt(a) )^2 = a
We also followed this procedure to rationalize the denominator of 93sqrt(13).
a/b=.a /3./.b /3.
a/b=a * sqrt(13)/b * sqrt(13)
a* a=a^2
( sqrt(a) )^2 = a