McGraw Hill Glencoe Algebra 2, 2012
MH
McGraw Hill Glencoe Algebra 2, 2012 View details
Standardized Test Practice

Exercise 12 Page 869

The formula that gives the balance y of an account earning compound interest is y=P( 1+ rn )^(nt), where P is the principal, r is the annual interest rate, t is the time in years, and n is the number of times the interest is compounded in one year.

$ 780.25

Practice makes perfect

We deposit $500 into an account paying 4.5 % interest compounded semiannually. We want to find the value of the account after 10 years. Our account earns compound interest, which means that interest is earned not only on the $500 we deposited but also on any earned interest. Let's recall the formula that gives the balance y of an account earning compound interest. y= P( 1+r/n )^(n t)In this formula, P is the principal or initial amount, r is the annual interest rate written in decimal form, t is the time in years, and n is the number of times the interest is compounded in one year. Let's pay close attention to the given scenario.

You deposit $ 500 in an account paying 4.5 % interest compounded semiannually.

We can immediately identify P as 500. Also, the interest rate, written as a decimal number, is 0.045. Since the interest is compounded semiannually, or 2 times a year, we have that n= 2. Finally, we want to find the value of the account after 10 years, so t = 10. Let's substitute these values into the formula and evaluate.

y=P( 1+r/n )^(nt)
y= 500( 1+0.045/2 )^(( 2)( 10))
â–¼
Evaluate
y=500( 1+0.045/2 )^(20)
y=500( 1+0.0225 )^(20)
y=500( 1.0225 )^(20)
y=500( 1.560509... )
y=780.254600...
y ≈ 780.25

The value of the account after 10 years rounded to the nearest penny is $ 780.25.