McGraw Hill Glencoe Algebra 2, 2012
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McGraw Hill Glencoe Algebra 2, 2012 View details
5. Law of Cosines
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Exercise 38 Page 828

Isolate c from the given equation. What are the necessary conditions for c to be a positive integer?

D

Practice makes perfect

We are told that c and d are different positive integers, for which 4c+d=26. We want to find the sum of all possible values of c. Let's start by isolating c from the given equation.

4c+d=26
4c=26-d
c=26-d/4

Since the equation has two different variables, there is not much more that we can do with it. However, remember that c and d are different positive integers, which means they are integers greater than 0.

Integers:& ... - 3, - 2, - 1, 0, 1, 2, 3, ... Positive Integers:& 1,2,3 ... Note that if c needs to be a positive integer, then 26-d4 needs to be a positive integer. Therefore, the expression in the numerator, 26-d, has to be divisible by the denominator, 4, so 26-d must be a multiple of 4. Since d is positive and we subtract it from 26, all possible multiples are less than or equal to 26 and greater than 0.

Multiple Multiple =26-d d
24 24=26-d 2
20 20=26-d 6
16 16=26-d 10
12 12=26-d 14
8 8=26-d 18
4 4=26-d 22

Now, knowing all possible values of d we can substitute them into the expression 26-d4 to find the possible values of c.

d 26-d/4 c=26-d/4
2 26- 2/4 6
6 26- 6/4 5
10 26- 10/4 4
14 26- 14/4 3
18 26- 18/4 2
22 26- 22/4 1

We have obtained all possible values of c. Recall that c and d have to be different positive integers, but in this case c and d are different in every instance. Finally, we can find the sum of all possible values of c. 6+5+4+3+2+1=21 The obtained sum corresponds to option D.