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Begin by using the Law of Sines if two angles and any side are given, or if two sides and an angle opposite one of them are given. Begin by using the Law of Cosines if two sides and their included angle are given, or if the three sides are given.
Law: Cosines
Missing Parts: H≈ 48^(∘), J≈ 25^(∘), K≈ 107^(∘)
We can use the Law of Sines and the Law of Cosines to find missing measurements in triangles that are not right triangles. Finding all of the missing measurements is called solving the triangle. To do this, we have to determine which of the two laws must be used first.
| Solving Triangles | |
|---|---|
| Given | Begin by Using |
| Two angles and any sides | Law of Sines |
| Two sides and an angle opposite one of them | Law of Sines |
| Two sides and their included angle | Law of Cosines |
| Three sides | Law of Cosines |
Let's determine which law to use first and then solve the triangle.
In â–³ H J K we are told that h= 18, j= 10, and k= 23. Let's draw this triangle to visualize the situation.
We have information about three sides. Therefore, we must start solving the triangle by using the Law of Cosines.
We will find the missing angle measures one at a time. Let's consider the Law of Cosines and adapt it to our triangle. k^2= h^2+ j^2-2 h jcos K We can substitute the given values into this equation and solve for K.
Substitute values
Calculate power and product
Add terms
LHS-424=RHS-424
.LHS /- 360.=.RHS /- 360.
Put minus sign in front of fraction
Rearrange equation
cos ^(- 1)(LHS)=cos ^(- 1)(RHS)
Use a calculator
Round to nearest integer
Since now we have three side lengths and one angle measure, we can use the Law of Sines. sin K/k=sin H/h Let's substitute k= 23, K= 107^(∘), and h= 18 into the above equation and solve for H.
Substitute values
LHS * 18=RHS* 18
Rearrange equation
sin ^(- 1)(LHS)=sin ^(- 1)(RHS)
Use a calculator
Round to nearest integer
Finally, we can use the Triangle Angle Sum Theorem to find the measure of J. 48^(∘) + J + 107^(∘)=180^(∘) ⇕ J= 25^(∘) We have completely solved the triangle.