McGraw Hill Glencoe Algebra 2, 2012
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McGraw Hill Glencoe Algebra 2, 2012 View details
5. Law of Cosines
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Exercise 13 Page 826

Use the Law of Cosines to find the missing side length.

a ≈ 6.9
B ≈ 41^(∘)
C ≈ 23^(∘)

Practice makes perfect

Let's begin by drawing â–³ ABC and labeling the lengths of the sides. We will also color code the opposite angles and sides. It will help us use the Law of Sines and Law of Cosines later.

Let's find the length of the side a, and measures of ∠ B, ∠ C one at a time.

Finding a

We are given two sides and their included angle. Therefore, we can use the Law of Cosines to find the third side. a^2 = b^2 + c^2 - 2bccos A Let's substitute b= 5, c= 3, and A = 116^(∘).

a^2 = b^2 + c^2 - 2bccos A
a^2 = 5^2 + 3^2 - 2( 5)( 3)cos 116^(∘)
â–¼
Solve for a
a^2 = 25 + 9 - 2(5)(3)cos 116^(∘)
a^2 = 25 + 9 - 30cos 116^(∘)
a^2 = 25 + 9 - (- 13.151134...)
a^2 = 25 + 9 + 13.151134...
a^2 = 47.151134...
a = sqrt(47.151134...)
a = 6.866668...
a ≈ 6.9

Finding m ∠ B

Now that we know the length of the side a, we can find m ∠ B using the Law of Sines. sin A/a =sin B/b Let's substitute a= 6.9, b= 5, and m ∠ A = 116^(∘) to isolate sin B.

sin A/a =sin B/b
sin 116^(∘)/6.9 = sin B/5
â–¼
Solve for sin B
5 sin 116^(∘)/6.9 = sin B
sin B =5 sin 116^(∘)/6.9

Now we can use the inverse sine ratio to find m ∠ B.

m ∠ B = sin ^(-1) (5 sin 116^(∘)/6.9)
m ∠ B = 40.63969...^(∘)
m ∠ B ≈ 41^(∘)

Finding m ∠ C

Finally, to find m ∠ C we can use the Triangle Angle Sum Theorem. This tells us that the measures of the angles in a triangle add up to 180^(∘). 116^(∘) + 41^(∘) + m ∠ C= 180^(∘) ⇔ m ∠ C ≈ 23^(∘)

Completing the Triangle

With all of the angle measures, we can complete our diagram.

Extra

The Law of Cosines can be visualized by drawing a triangle and labeling angles and sides.

Triangle

Similarly, the Law of Sines can also be visualized by drawing a triangle and labeling angles and sides.

triangle