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Think of two investments that have the same expected values but one of them is significantly more risky.
See solution.
Let's begin by recalling the concept of an expected value. The expected value of a discrete random variable is the weighted average of the values of the variable. E(X)=∑ [X* P(X)] In other words, it is the sum of the products of every possible value of X and its corresponding probability P(X). Now let's think of two types of investments.
| Type of Investment | Description |
|---|---|
| 1-year treasury bond | We lend money to the U.S. government and receive our money back, plus interest, after 1 year. The interest that we earn depends on the treasury rate. |
| Investing in a start-up company | We invest money in a start-up and could potentially make a serious profit after 1 year. However, most start-ups fail within the first year, so the probability we end up with nothing is about 80 %. |
| Investment | Standard Deviation | Simplify |
|---|---|---|
| Treasury Bond | σ = sqrt([101-101]^2* 1) | 0 |
| Start-up | σ = sqrt([505-101]^2* 2/10+[0-101]^2*8/10) | 202 |
As we said before, bonds are considered a risk-free investment, so their standard deviation is equal to $0. In our example, investing in a start-up is significantly more risky with a standard deviation of $202.
| Investment | Expected Value | Standard Deviation |
|---|---|---|
| Treasury Bond | $101 | $0 |
| Start-up | $101 | $202 |
Therefore, when we want to make an investment, we should consider both the expected values and the standard deviations. While the expected values can be equal, the difference in risks of the investments can be seen in their standard deviations. The choice we make should be based on how much we are willing to lose.