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The expected value is what you get if you add up products of the possible values of cards and the corresponding probabilities of drawing them.
First, calculate the expected value of spades in hand if you are dealt only one card.
7
1.75
The expected value of a card that is drawn from a standard deck of cards is the weighted sum of all the card values.
E(Value of a Card)= ∑ [Value* P(Value)]
To find it, we will first make a table containing the cards and their frequencies in the deck. There are 4 suits of cards, therefore there are 4 cards of each value.
| Card Value | Number of Cards With The Same Value (Frequency) |
|---|---|
| 1 (Ace) | 4 |
| 13 (King) | 4 |
| 12 (Queen) | 4 |
| 11 (Jack) | 4 |
| 10 | 4 |
| 9 | 4 |
| 8 | 4 |
| 7 | 4 |
| 6 | 4 |
| 5 | 4 |
| 4 | 4 |
| 3 | 4 |
| 2 | 4 |
Since the number of cards with each value is 4, the probability of drawing a card with each value is equal to 4 divided by the total number of cards, 52.
| Card Value | P(Value) |
|---|---|
| 1 (Ace) | 4/52 |
| 13 (King) | 4/52 |
| 12 (Queen) | 4/52 |
| 11 (Jack) | 4/52 |
| 10 | 4/52 |
| 9 | 4/52 |
| 8 | 4/52 |
| 7 | 4/52 |
| 6 | 4/52 |
| 5 | 4/52 |
| 4 | 4/52 |
| 3 | 4/52 |
| 2 | 4/52 |
Now, we can calculate the products of the card values and their probabilities.
| Card Value | P(Value) | Value* P(Value) |
|---|---|---|
| 1 (Ace) | 4/52 | 1*4/52=4/52 |
| 13 (King) | 4/52 | 13*4/52=52/52 |
| 12 (Queen) | 4/52 | 12*4/52=48/52 |
| 11 (Jack) | 4/52 | 11*4/52=44/52 |
| 10 | 4/52 | 10*4/52=40/52 |
| 9 | 4/52 | 9*4/52=36/52 |
| 8 | 4/52 | 8*4/52=32/52 |
| 7 | 4/52 | 7*4/52=28/52 |
| 6 | 4/52 | 6*4/52=24/52 |
| 5 | 4/52 | 5*4/52=20/52 |
| 4 | 4/52 | 4*4/52=16/52 |
| 3 | 4/52 | 3*4/52=12/52 |
| 2 | 4/52 | 2*4/52=8/52 |
To find the expected card value we need to sum the values from the last column. Let's do it! E(Value of a Card)= 4/52+52/52+48/52+44/52+40/52+... = 364/52 = 7 The expected value of a card drawn from the deck is 7.
P(Value)= 4/52
Factor out 4/52
We found that the expected card value is the sum of all the card values multiplied by 452. Let's calculate it! E(Value of a Card)= 4/52(1+2+3+...+13) = 4/52(91) = 7
We are asked to calculate the expected value of the number of spades we get if we are dealt 7 cards, replacing the card each time. First, let's solve something simpler — the expected number of spades if we are dealt only 1 card.
We will first find the probabilities of drawing a spade and not a spade. There are 13 spades and 39 cards of other suits in the deck. To find the probabilities of drawing a spade and a card other than spade, we need to divide 13 and 39 by the total number of cards, 52.
| Card Suit | Number of Cards | Probability |
|---|---|---|
| Spade | 13 | 13/52=1/4 |
| Not Spade | 39 | 39/52=3/4 |
| The Card We Drew | Spades in Hand | Probability |
|---|---|---|
| Spade | 1 | 1/4 |
| Not Spade | 0 | 3/4 |
With this information, we can calculate the expected value of spades in hand after drawing one card! E(Number of Spades,1Draw)= 1* 1/4+ 0* 34=1/4
Now, let's try to calculate the expected number of spades after we are dealt 7 cards. Notice that since we are dealt cards with replacement, we can think of this event as 7 independent card draws. The expected value of spades after 7 independent card draws is equal to 7 times the expected number of spades after 1 draw. E(Number of Spades,7Draws)= 7* E(Number of Spades,1Draw) Earlier, we found that the expected number of spades after 1 draw is 14. Let's substitute that into our equation. 7* E(Number of Spades,1Draw)= 7* 1/4=1.75 The expected value of spades after we are dealt 7 cards with replacement is 1.75. This means that on average we can expect to have around 2 spades in hand after we are dealt 7 cards with replacement.