McGraw Hill Glencoe Algebra 2, 2012
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McGraw Hill Glencoe Algebra 2, 2012 View details
3. Probability Distributions
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Exercise 12 Page 747

Practice makes perfect

a

The expected value of a card that is drawn from a standard deck of cards is the weighted sum of all the card values.

E(Value of a Card)= ∑ [Value* P(Value)] To find it, we will first make a table containing the cards and their frequencies in the deck. There are 4 suits of cards, therefore there are 4 cards of each value.

Card Value Number of Cards With The Same Value (Frequency)
1 (Ace) 4
13 (King) 4
12 (Queen) 4
11 (Jack) 4
10 4
9 4
8 4
7 4
6 4
5 4
4 4
3 4
2 4

Since the number of cards with each value is 4, the probability of drawing a card with each value is equal to 4 divided by the total number of cards, 52.

Card Value P(Value)
1 (Ace) 4/52
13 (King) 4/52
12 (Queen) 4/52
11 (Jack) 4/52
10 4/52
9 4/52
8 4/52
7 4/52
6 4/52
5 4/52
4 4/52
3 4/52
2 4/52

Now, we can calculate the products of the card values and their probabilities.

Card Value P(Value) Value* P(Value)
1 (Ace) 4/52 1*4/52=4/52
13 (King) 4/52 13*4/52=52/52
12 (Queen) 4/52 12*4/52=48/52
11 (Jack) 4/52 11*4/52=44/52
10 4/52 10*4/52=40/52
9 4/52 9*4/52=36/52
8 4/52 8*4/52=32/52
7 4/52 7*4/52=28/52
6 4/52 6*4/52=24/52
5 4/52 5*4/52=20/52
4 4/52 4*4/52=16/52
3 4/52 3*4/52=12/52
2 4/52 2*4/52=8/52

To find the expected card value we need to sum the values from the last column. Let's do it! E(Value of a Card)= 4/52+52/52+48/52+44/52+40/52+... = 364/52 = 7 The expected value of a card drawn from the deck is 7.

Alternative Solution

Different Approach
The probabilities of drawing cards with different values are the same — they are equal to 452. Let's try to modify the equation for the expected value using this information.

E(Value of a Card)= ∑ [Value* P(Value)]
E(Value of a Card)= ∑ [Value* 4/52]
E(Value of a Card)= 4/52 ∑ [Value]

We found that the expected card value is the sum of all the card values multiplied by 452. Let's calculate it! E(Value of a Card)= 4/52(1+2+3+...+13) = 4/52(91) = 7

b

We are asked to calculate the expected value of the number of spades we get if we are dealt 7 cards, replacing the card each time. First, let's solve something simpler — the expected number of spades if we are dealt only 1 card.

Expected Number of Spades After Drawing 1 Card

We will first find the probabilities of drawing a spade and not a spade. There are 13 spades and 39 cards of other suits in the deck. To find the probabilities of drawing a spade and a card other than spade, we need to divide 13 and 39 by the total number of cards, 52.

Card Suit Number of Cards Probability
Spade 13 13/52=1/4
Not Spade 39 39/52=3/4
The amount of spades in hand if we get a spade after drawing one card is 1. The corresponding probability to this event is 14. On the other hand, having 0 spades in hand after drawing one card has a probability of 34.

The Card We Drew Spades in Hand Probability
Spade 1 1/4
Not Spade 0 3/4

With this information, we can calculate the expected value of spades in hand after drawing one card! E(Number of Spades,1Draw)= 1* 1/4+ 0* 34=1/4

Expected Number of Spades After Drawing 7 Cards

Now, let's try to calculate the expected number of spades after we are dealt 7 cards. Notice that since we are dealt cards with replacement, we can think of this event as 7 independent card draws. The expected value of spades after 7 independent card draws is equal to 7 times the expected number of spades after 1 draw. E(Number of Spades,7Draws)= 7* E(Number of Spades,1Draw) Earlier, we found that the expected number of spades after 1 draw is 14. Let's substitute that into our equation. 7* E(Number of Spades,1Draw)= 7* 1/4=1.75 The expected value of spades after we are dealt 7 cards with replacement is 1.75. This means that on average we can expect to have around 2 spades in hand after we are dealt 7 cards with replacement.