McGraw Hill Glencoe Algebra 2, 2012
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Exercise 14 Page 781

The maximum error of estimate E for a population mean is given by E = z * ssqrt(n).

G

Practice makes perfect

We want to calculate the maximum error of estimate for the time spent in the gym. The maximum error of estimate E is given by the following formula. E = z * s/sqrt(n)Notice the mean time is not needed to calculate the maximum error of estimate. The z-value corresponds to a particular confidence level, s is the standard deviation of the sample, and n is the sample size. Let's begin by finding the z-value that corresponds to the given confidence level. The table shows the most commonly used levels and corresponding z-values.

Confidence Level z-value
90 % 1.645
95 % 1.960
99 % 2.576

We want to use 95 % confidence level, so from the table we know z will be equal to 1.960. The survey asked 300 members of the fitness club, meaning that n = 300. A standard deviation of 8.6 minutes is given, so s = 8.6. We are ready to calculate the maximum error of estimate E.

E = z * s/sqrt(n)
E = 1.960 * 8.6/sqrt(300)
â–¼
Simplify right-hand side
E = 1.960 * 8.6/sqrt(300)
E = 16.856/sqrt(300)
E = 0.973181 ...
E ≈ 0.97

The maximum error of estimate E is about 0.97, which corresponds to answer G.