McGraw Hill Glencoe Algebra 2, 2012
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McGraw Hill Glencoe Algebra 2, 2012 View details
Practice Test
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Exercise 12 Page 781

11.2 < X < 21.6

Practice makes perfect

We have been told that the random variable is normally distributed with a mean of μ = 16.4 and a standard deviation of σ = 2.6. We want to find the range of values that represent the middle 95 % of the distribution. P(aP(μ-z < X < μ + z) = 95 % Let's recall the Empirical Rule for the normal distribution. According to this rule, approximately 95 % of the data fall within 2σ from the mean. P(μ - 2σ < X < μ + 2σ) = 95 % Knowing that μ=16.4 and σ=2.6, let's find both ends of the range.

μ- 2σ < X < μ + 2σ
16.4 - 2( 2.6) < X < 16.4 + 2( 2.6)
16.4 - 5.2 < X < 16.4 + 5.2
11.2 < X < 21.6

We found the range that represents the middle 95 % of the distribution. P( 11.2 < X < 21.6 ) = 95 % We can now use the Empirical Rule to help us visualize the data with these parameters. Let's shade the areas that satisfy the compound inequality 11.2