McGraw Hill Glencoe Algebra 2, 2012
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McGraw Hill Glencoe Algebra 2, 2012 View details
6. The Binomial Theorem
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Exercise 49 Page 703

Practice makes perfect
a When working with speed, it's often helpful to use a table and the equation, d=rt, as a basis for our equation. In this case, we are solving for time, so t= dr. Let's start by organizing our information in a table.
Distance, d Rate, r Time, t=d/r
Interstate 150 x 150/x
Highway 130 x-10 130/x-10
Total Trip 280 70 4

From the table, we can see the expression for time on the interstate is 150x and on the highway is 130x-10.

b The equation to find the speed limit uses the information that the total trip took 4 hours. We can use the expressions for time that we developed in Part A to form our equation.

150/x+ 130/x-10=4
â–¼
Simplify left-hand side
150+ 130x/x-10=4x
150(x-10) + 130x = 4x(x-10)
150x - 1500 + 130x = 4x(x-10)
150x - 1500 + 130x = 4x^2-40x
280x-1500=4x^2-40x
-1500=4x^2-320x
0 = 4x^2-320x+1500
4x^2-320x+1500=0

Now, we have a quadratic equal to zero, we can factor and use the Zero Product Property to solve.

4x^2-320x+1500=0
â–¼
Solve for x
x^2 - 80x + 375=0
(x-75)(x-5)=0
lcx-75=0 & (I) x-5=0 & (II)
lx=75 x-5=0
lx=75 x=5

Since we get a negative speed for the highway when we take 10 from 5, the interstate speed is 75 mph and highway speed is 75-10, or 65 mph.