McGraw Hill Glencoe Algebra 2, 2012
MH
McGraw Hill Glencoe Algebra 2, 2012 View details
Study Guide and Review
Continue to next subchapter

Exercise 61 Page 714

Use the Binomial Theorem to write the expansion in sigma notation.

193 536x^2y^5

Practice makes perfect
We want to find the sixth term of the expansion of the given expression. ( 3x+ 4y)^7To do so, we will use the Binomial Theorem to write the expansion in sigma notation. (a+b)^n=∑_(k=0)^n n!/k!(n-k)!a^(n-k)b^k For our expression, we have that a= 3x, b= 4y, and n= 7. Since k starts at 0, for the sixth term we have k=5. Remember that we do not have to find the sum — we only need to find one of the terms. Therefore, we will only consider the argument of the summation notation instead of the entire sum.
n!/k!(n-k)!a^(n-k)b^k
7!/5!( 7-5)!( 3x)^(7-5)( 4y)^()darkorange5
Simplify
7!/5!(2!)(3x)^2(4y)^5

2!=2

7!/5!(2)(3x)^2(4y)^5

n!=n* (n-1)!

7(6!)/5!(2)(3x)^2(4y)^5

n!=n* (n-1)!

7(6)(5!)/5!(2)(3x)^2(4y)^5
7(6)/2(3x)^2(4y)^5
7(3)(3x)^2(4y)^5
21(3x)^2(4y)^5
21(3)^2x^2(4)^5y^5
21(9)x^2(1024)y^5
193 536x^2y^5