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McGraw Hill Glencoe Algebra 2, 2012
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McGraw Hill Glencoe Algebra 2, 2012 View details
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Exercise 53 Page 713

The given rule means that each iterate of the function is found by multiplying the previous value by 6 and then subtracting 1.

11, 65, 389

Practice makes perfect

We are asked to find the first three iterates of a function, given an initial value. x_0&=2 f(x)&=6x-1 Let's use a table to organize our calculations.

n x_n f(x)=6x-1 x_(n+1)
0 x_0= 2 6 x_0-1=6( 2)-1 11
1 x_1= 11 6 x_1-1=6( 11)-1 65
2 x_2= 65 6 x_2-1=6( 65)-1 389
3 x_3= 389 - -

Therefore, the first three iterates of the function are 11, 65, and 389.

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Exercises 12 (Page 711)
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