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- 3, 1, 5, 9, 13
We are asked to write the first five terms of a sequence, given a recursive formula. a_1&=- 3 a_(n+1)&=a_n+4 To do so, we will use a table. Notice that to find a_2 we will substitute n=1, to find a_3 we will substitute n=2, and so on.
| n | a_(n+1)=a_n+4 | a_n+4 | a_(n+1) |
|---|---|---|---|
| - | a_1=- 3 | - | - 3 |
| 1 | a_(1+1)=a_1+4 | a_1+4= - 3+4 | 1 |
| 2 | a_(2+1)=a_2+4 | a_2+4= 1+4 | 5 |
| 3 | a_(3+1)=a_3+4 | a_3+4= 5+4 | 9 |
| 4 | a_(4+1)=a_4+4 | a_4+4= 9+4 | 13 |
Therefore, the first five terms of the sequence are - 3, 1, 5, 9, and 13.