5. Recursion and Iteration
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Use the initial value as the input of a function rule. This will give us the first output value.
21, 1769, 12 517 449
x_0&=-2 f(x)& = 4x^2+5 To do so, we will use a table.
| n | x_n | f(x)=4x^2+5 | x_(n+1) |
|---|---|---|---|
| 0 | x_0= -2 | 4 x_0^2+5=4( -2)^2+5 | 21 |
| 1 | x_1= 21 | 4 x_1^2+5=4( 21)^2+5 | 1769 |
| 2 | x_2= 1769 | 4 x_2^2+5=4( 1769)^2+5 | 12 517 449 |
| 3 | x_3= 12 517 449 | - | - |
Therefore, the first three iterates of the function are 21, 1769 and 12 517 449.