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McGraw Hill Glencoe Algebra 2, 2012

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McGraw Hill Glencoe Algebra 2, 2012 View details

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Exercise 3 Page 657

Gather all of the variable terms on one side of the equation and all of the constant terms on the other side.

3

Practice makes perfect

To solve an equation, we should first gather all of the variable terms on one side and all of the constant terms on the other side using the Properties of Equality.

23 - 5x = 8

LHS-23=RHS-23

- 5x = 8 - 23

Subtract term

- 5x = - 15

.LHS /(- 5).=.RHS /(- 5).

x = 3

The solution to the equation is x = 3.

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