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McGraw Hill Glencoe Algebra 2, 2012

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McGraw Hill Glencoe Algebra 2, 2012 View details

3. Solving Equations

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Exercise 14 Page 22

Gather all of the variable terms on one side of the equation and all of the constant terms on the other side.

y=-4

Practice makes perfect

To solve an equation, we should first gather all of the variable terms on one side of the equation and all of the constant terms on the other side, using the Properties of Equality. In this case, we need to start by using the Addition Property of Equality to isolate -6y.

-6y-8=16

LHS+8=RHS+8

-6y-8+8=16+8

Add terms

-6y=24

Now we can fully isolate y using Division Property of Equality.

-6y=24

.LHS /(-6).=.RHS /(-6).

-6y/-6=24/-6

Calculate quotient

y=-4

The solution to the equation is y=-4. We can check our solution by substituting it into the original equation.

-6y-8=16

y= -4

-6( -4)-8 ? = 16

▼

Simplify

MultNegNegOnePar

- a(- b)=a* b

24-8 ? = 16

Subtract term

16=16

Since the left-hand side is equal to the right-hand side, our solution is correct.

Subchapter links

Check Your Understanding p.22

Practice and Problem Solving p.22-24

H.O.T. Problems p.24

Standardized Test Practice p.25

Spiral Review p.25

Skills Review p.25