McGraw Hill Glencoe Algebra 2, 2012
MH
McGraw Hill Glencoe Algebra 2, 2012 View details
1. Expressions and Formulas
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Exercise 27 Page 8

Practice makes perfect
a

We are given the radius of the Earth's orbit. We can substitute the given radius into the given formula to get the circumference of the orbit. Let's do it!

C=2Ï€ r
C=2Ï€( 93 000 000)
C=584 336 233.56770...
C≈ 584 336 233.6

The circumference of Earth's orbit is about 584 336 233.6 miles.

b

Earth's travel speed around the Sun is equal to 66 698 miles per hour. From Part A, we know that the circumference of Earth's orbit is about 584 336 233.6 miles. To find to find the number of hours it takes Earth to revolve around the Sun, we can use the given formula.

T=C/V
T=584 336 233.6/66 698
T=8760.925868 ...
T≈ 8761

It takes Earth about 8761 hours to revolve around the Sun.

c

In part B, we obtained that it takes Earth about 8761 hours to go around the Sun. Let's see how many days 8761 hours is. Since there are 24 hours in a day, we will divide this number by 24.

8761/24≈ 365 Since there are 365 days in a year, we indeed proved — based on the given data — that it takes about one year for Earth to go around the Sun.