McGraw Hill Glencoe Algebra 2, 2012
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McGraw Hill Glencoe Algebra 2, 2012 View details
8. The Pythagorean Theorem
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Exercise 18 Page P23

Think of a situation where perpendicular lines can be used as a model.

See solution.

Practice makes perfect

Let's create a problem! Yours will be different, but let's go through one together.

Statement of an Application Problem

Mr Brown needs to clean the gutter on his house. The gutter is 8 feet above the ground and there is a 3.5 feet wide flower bed next to the wall of the house. What is the minimum length of the ladder that can reach the gutter over the flower bed?

Solution of the Problem

The foot of the ladder needs to be 3.5 feet away from the wall and it needs to reach 8 feet high on the wall. The ladder, the horizontal flower bed, and the vertical wall form a right triangle.

The length of the two legs are given, and we are asked to find the length of the hypotenuse. The Pythagorean Theorem states the connection between these lengths. c^2=a^2+b^2 We can substitute the known values in this equation to find the answer to the question.

c^2=a^2+b^2
c^2= 3.5^2+ 8^2
â–¼
Solve for c
c^2=12.25+64
c^2=76.25
c=sqrt(76.26)
c≈ 8.73

The minimum length of the ladder that can reach the gutter over the flower bed is about 8.73 feet.