Does the occurrence of the first event affect the probability of the second event?
1/6
Practice makes perfect
If the occurrence of one event does not affect the probability of a second event, then they are said to be independent events. If A and B are independent events, we calculate P(AandB) by multiplying P(A) and P(B).
P(AandB)=P(A)* P(B)
Note that rolling two of the same number means rolling any number the first time and rolling the same number the second time.
P(two of the same number)=
P(any number and the same number)
Let A be "rolling a number from 1 to 6" and B be "rolling the same number as before." Thus A and B means "two of the same number". The outcome of rolling a die once does not affect the outcome of a second roll. Therefore, they are independent events.
P(A and B)= P(A) * P(B)
A regular die has six faces, and in the first time we can get any of the six of them. The probability after rolling a regular die is 6 6. The probability of obtaining the same number as before after rolling a regular die is 1 6. Let's substitute 66 for P(A) and 16 for P(B) in the equation.
