body{margin:0;} noscript{z-index: 10000; position: fixed; display: block; height: 100%; width: 100%; background: #fff;} noscript .fa{font-size: 40px; display:block; color: #daa520;} noscript div{margin-top: 6%; padding-left: 20px; padding-right: 20px; text-align: center;} ! You must have JavaScript enabled to use this site.

McGraw Hill Glencoe Algebra 1, 2017

MH

McGraw Hill Glencoe Algebra 1, 2017 View details

3. Solving Multi-Step Equations

Continue to next subchapter

Exercise 1 Page 97

Gather all of the variable terms on one side of the equation and all of the constant terms on the other side.

m=- 5

Practice makes perfect

To solve an equation, we gather all of the variable terms on one side of the equation and all of the constant terms on the other side using the Properties of Equality. We will begin with the Subtraction Property of Equality to eliminate the addition.

3m+4=- 11

LHS-4=RHS-4

3m+4-4=- 11-4

Subtract terms

3m=- 15

Now we will use the Division Property of Equality to eliminate the coefficient.

3m=- 15

.LHS /3.=.RHS /3.

3m/3=- 15/3

Calculate quotient

m=- 5

The solution to the equation is m= - 5. We can check our solution by substituting it into the original equation.

3m+4=- 11

m= - 5

3( - 5)+4? =- 11

▼

Simplify

a(- b)=- a * b

- 15+4? =- 11

Add terms

- 11=- 11

Since the left-hand side is equal to the right-hand side, our solution is correct.

Subchapter links

Check Your Understanding p.97

Practice and Problem Solving p.98-99

H.O.T. Problems p.99

Preparing for Assessment p.100