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Start by identifying the values of a, b, and c.
(a+8)(2a-3)
Here we have a quadratic trinomial of the form ax^2+bx+c, where |a| ≠1 and there are no common factors. To factor this expression we will rewrite the middle term, bx, as two terms. The coefficients of these two terms will be factors of ac whose sum must be b.
2a^2+13a-24
We have that a= 2, b=13, and c=24. There are now three steps we need to follow in order to rewrite the above expression.
c|c|c|c 1^(st)Factor &2^(nd)Factor &Sum &Result - 1 &48 &- 1 + 48 &47 - 2 &24 &- 2 + 24 &22 - 3 & 16 & - 3 + 16 &13 - 4 &12 &- 4 + 12 &8 - 6 &8 &- 6 + 8 &2
Finally, we will factor the last expression obtained.
Factor out a
Factor out 8
Factor out (2a-3)
Distribute (2a-3)
Distribute a
Distribute a
Subtract term
We can see above that after expanding and simplifying, the result is the same as the given expression. Therefore, we can be sure our solution is correct!