McGraw Hill Glencoe Algebra 1, 2012
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McGraw Hill Glencoe Algebra 1, 2012 View details
8. Difference of Squares
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Exercise 53 Page 520

Notice that the given equation follows a special pattern and it can be factored as a difference of squares.

- 45, 45

Practice makes perfect

We want to solve the given equation by factoring. Let's consider our equation. 81-1/25x^2=0 Notice that this equation follows a special pattern. It can be factored as a difference of squares. Let's factor the equation!

81-1/25x^2=0
9^2-(1/5)^2x^2=0
9^2-(1/5x)^2=0
(9+1/5x)(9-1/5x)=0

Now we are ready to use the Zero Product Property.

(9+1/5x)(9-1/5x)=0
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Solve using the Zero Product Property
lc9+ 15x=0 & (I) 9- 15x=0 & (II)
l 15x=- 9 9- 15x=0
lx=- 45 9- 15x=0
lx=- 45 - 15x=-9
lx=- 45 x=45

We found that the solutions to the given equation are x=- 45 and x=45. To check our answer, we will graph the related function, y=81- 15x^2, using a calculator. Since 125=0.04, we will use decimal instead of the fraction.

We can see that the x-intercepts are - 45 and 45. Therefore, our solutions are correct.