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The volume of a pyramid is 13 the area of the base times the height.
Substitute the given values for b into the formula from Part B.
Use the table you created in Part C.
Diagram:
Equation: h=216/b^2
Table:
| b | h |
|---|---|
| 1 | 216 |
| 3 | 24 |
| 6 | 6 |
| 9 | 2 23 |
| 12 | 1 12 |
If b
We are asked now to suppose the volume of the pyramid is 72 cm^3 and to write an equation to find the height h. To do so, we will use the fact that the volume of a pyramid is 13 the area of the base times the height.
LHS * 3=RHS* 3
.LHS /b^2.=.RHS /b^2.
Rearrange equation
We will create a table to show the values of h when b=1, 3, 6, 9, and 12. To do so, we will use the formula h= 216b^2 that we found in part B.
| b | h=216/b^2 | h |
|---|---|---|
| 1 | 216/1^2 | 216 |
| 3 | 216/3^2 | 24 |
| 6 | 216/6^2 | 6 |
| 9 | 216/9^2 | 2 23 |
| 12 | 216/12^2 | 1 12 |
In this part, we will write an inequality for the possible lengths of b such that b