McGraw Hill Glencoe Algebra 1, 2012
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McGraw Hill Glencoe Algebra 1, 2012 View details
2. Solving Inequalities by Multiplication and Division
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Exercise 41 Page 296

Practice makes perfect
a

Let's draw a pyramid with a square base b cm long and a height of h cm.

b

We are asked now to suppose the volume of the pyramid is 72 cm^3 and to write an equation to find the height h. To do so, we will use the fact that the volume of a pyramid is 13 the area of the base times the height.

V=1/3 A h As the base is a square with a side length of b cm, its area is b^2 cm^2. Since we know the volume, we can now write the equation as follows. 72=1/3* b^2* h Now let us rearrange our equation to solve for the height h.

72=1/3* b^2* h
216=b^2* h
216/b^2=h
h=216/b^2

c

We will create a table to show the values of h when b=1, 3, 6, 9, and 12. To do so, we will use the formula h= 216b^2 that we found in part B.

b h=216/b^2 h
1 216/1^2 216
3 216/3^2 24
6 216/6^2 6
9 216/9^2 2 23
12 216/12^2 1 12
d

In this part, we will write an inequality for the possible lengths of b such that bless than h, we also have that b is less than 6.

b < 6 Finally, we are also asked to write an inequality for the possible lengths of h such that b>h. This time, notice that, if b is greater than h, then h is less than 6. Therefore, we can write the inequality for h as follows. h < 6