McGraw Hill Glencoe Algebra 1, 2012
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McGraw Hill Glencoe Algebra 1, 2012 View details
8. Literal Equations and Dimensional Analysis
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Exercise 32 Page 130

The word equals divides the sentence into what should be on the left-hand side and what should be on the right-hand side of the equation.

Equation: 34p-2= 56r+5
Solution: r=9/10p-42/5

Practice makes perfect
Every equation has an equals sign and values or expressions on either side of it. Key phrases, such as is, is equal to, and equals tell us about the placement of the equals sign. Three fourths of a numberpless two = five sixths of another numberrplus five. On the left-hand side, we have the keywords of and less. These words tell us the operations that will be used in our equation. Of indicates multiplication, while less indicates subtraction. Three fourths of a numberpless two 34 p - 2 On the right-hand side, the keywords are of and plus. Once again, of tells us to multiply, and plus tells us to add. Five sixths of another numberrplus five 56 r + 5 Putting these sides together, we have a complete equation. 34 p- 2=56 r+ 5 Finally, we can solve the equation we have written. We will do this using inverse operations and following the Properties of Equality.
3/4 p - 2 = 5/6 r + 5
3/4 p - 2 - 5 = 5/6 r + 5 - 5
3/4 p - 7 = 5/6 r
6/5 ( 3/4 p - 7 ) = 6/5 * 5/6 r
6/5 ( 3/4 p - 7 ) = r
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Simplify left-hand side
6/5 * 3/4 p - 6/5 * 7 = r
18/20 p - 42/5 = r
9/10 p - 42/5 = r
r = 9/10 p - 42/5