McGraw Hill Glencoe Algebra 1, 2012
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McGraw Hill Glencoe Algebra 1, 2012 View details
8. Literal Equations and Dimensional Analysis
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Exercise 31 Page 130

The word equals divides the sentence into what should be on the left-hand side and what should be on the right-hand side of the equation.

Equation: 910g=7+ 23k
Solution: k = 3/2 ( 9/10g-7 )

Practice makes perfect
Every equation has an equals sign and values or expressions on either side of it. Key phrases, such as is, is equal to, is the same as, and equals tell us about the placement of the equals sign. Nine tenths of a numberg = seven plus two thirds of another numberk. On the left-hand side, we have the keyword of. This word tells us the operation that will be used in our equation, which for of is multiplication. Nine tenths of a numberg 910 g On the right-hand side, the keywords are plus and of. Once again, of tells us to multiply, and plus tells us to add. Sevenplustwo thirds of another numberk 7 + 23 k Putting these sides together, we have a complete equation. 910 g= 7+23 k Finally, we can solve the equation we have written. We will do this by using inverse operations and following the Properties of Equality.
9/10g=7+2/3k
9/10g-7=7+2/3k-7
9/10g-7=2/3k
3/2 ( 9/10g-7 ) =3/2 * 2/3k
3/2 ( 9/10g-7 ) = k
k = 3/2 ( 9/10g-7 )