Exercise 2 Page 820

We are given a table that shows the number of calories in twelve different snacks.

Number of Calories in Snacks
$122$	$91$	$149$	$121$
$64$	$138$	$342$	$72$
$179$	$105$	$99$	$114$

We are asked to find the mean absolute deviation. Let's recall the formula to find it. In this formula $n$ is the number of values, $x_n$ are the data values, and $\overline{x}$ is the mean of the data. Therefore, we need to find the mean of the data first. To do so, we will add all the values and divide the sum by $12.$ Now we can find the absolute value of the difference between each data value and the mean. Let's do it!

$x_i$	$|\overline{x}-x_i|$	Simplify
$122$	$|133-122|$	$11$
$91$	$|133-91|$	$42$
$149$	$|133-149|$	$16$
$121$	$|133-121|$	$12$
$64$	$|133-64|$	$69$
$138$	$|133-138|$	$5$
$342$	$|133-342|$	$209$
$72$	$|133-72|$	$61$
$179$	$|133-179|$	$46$
$105$	$|133-105|$	$28$
$99$	$|133-99|$	$34$
$114$	$|133-114|$	$19$

Now let's add all of these values together and divide the sum by $12$ to find the mean absolute deviation. The mean absolute deviation of the calories of each snack is $46$ calories. Therefore, the correct answer is F.