We are given a table that shows the number of calories in twelve different snacks.

We are asked to find the mean absolute deviation. Let's recall the formula to find it.

MAD = \frac{∣ x - x _{1} ∣ + ∣ x - x _{2} ∣ + \dots + ∣ x - x _{n} ∣}{n}

In this formula

n

is the number of values,

x_{n}

are the data values, and

\overline{x}

is the mean of the data. Therefore, we need to find the mean of the data first. To do so, we will add all the values and divide the sum by

12 .

\overline{x} = (122 + 91 + 149 + 121 + 64 + 138 + 342 + 72 + 179 + 105 + 99 + 114) / 12

Add terms

\overline{x} = \frac{1 5 9 6}{1 2}

Calculate quotient

\overline{x} = 133

Now we can find the absolute value of the difference between each data value and the mean. Let's do it!

Now let's add all of these values together and divide the sum by

12

to find the mean absolute deviation.

MAD = (11 + 42 + 16 + 12 + 69 + 5 + 209 + 61 + 46 + 28 + 34 + 19) / 12

Add terms

MAD = \frac{5 5 2}{1 2}

Calculate quotient

MAD = 46

The mean absolute deviation of the calories of each snack is

46

calories. Therefore, the correct answer is F.

Exercise