Manipulating Radical Functions

Given that $f(x)=\sqrt[3]{2x}$ and $g(x)=\text{-}11\sqrt[3]{2x},$ we will define $(f+g)(x)$ and $(f-g)(x).$ Let's begin with the sum of the functions.

Adding Two Functions

Note that $(f+g)(x)=f(x)+g(x).$ From here, we will substitute the given function rules and find the sum.

Subtracting Two Functions

Note that $(f-g)(x)=f(x)-g(x),$ so we can proceed in the same way as we add two functions.