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If a segment parallel to one of the sides of a triangle is drawn between the other sides, the segment divides the other two sides proportionally.
Based on the diagram, the following relation holds true.
If DE ∥ AB, then AD/DC=BE/EC
Therefore, by the Angle-Angle Similarity Theorem, △ ABC and △ DEC are similar. Consequently, their corresponding sides are proportional. △ ABC ~ △ DEC ⇓ AC/DC=BC/EC Applying the Segment Addition Postulate, both numerators can be rewritten. AC &= AD+DC BC &= BE+EC Substituting these expressions into the equation above, the required proportion will be obtained.
AC= AD+DC, BC= BE+EC
Write as a sum of fractions
Simplify quotient
LHS-1=RHS-1