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Two polygons are similar if and only if both of the following two properties hold.
| Conditional Statement | Two polygons are similar if the corresponding angles are congruent and the corresponding sides are proportional. |
|---|---|
| Converse | If the corresponding angles in two polygons are congruent and the corresponding sides are proportional, then the polygons are similar. |
Consider and prove each statement one at a time.
If two polygons are similar, then a similarity transformation that maps one polygon to the other exists. Consider how that relationship affects the corresponding angles and sides of the similar polygons.
These observations conclude the proof of the conditional statement.
Consider two polygons with congruent corresponding angles and proportional corresponding sides. The proof here will be carried out for quadrilaterals ABCD and PQRS, but it can be generalized to any polygon.
Since the corresponding angles are congruent and the corresponding sides are proportional, the following statements are true. ∠ A&≅∠ P ∠ B&≅∠ Q ∠ C&≅∠ R ∠ D&≅∠ S PQ/AB=QR/BC&=RS/CD=SP/DA To show that the polygons ABCD and PQRS are similar, a similarity transformation can be built to map ABCD to PQRS. This can be done in several ways, so here is just an example of one possibility.
The following table contains some observations about the position of points A'', B'', C'', and D'' relative to PQRS.
| Observation | Justification |
|---|---|
| P=A'' | The translation moves A to P and, since this is the center of rotation, it stays there. |
| B'' is on PQ | This is how the angle of rotation was chosen. |
| D'' is on PS | This is true, because by assumption ∠ A is congruent to ∠ P and because rigid motions preserve angle measures. Note that, in this case, the orientation of ABCD and PQRS is the same. If the orientations are different, then a reflection of A''B''C''D'' in line PQ is also needed to match the orientations of the polygons. |
The following table contains some observations about the position of points A''', B''', C''', and D''' relative to PQRS.
| Observation | Justification |
|---|---|
| P=A''' | The translation moves A to P and, since this is the center of rotation and also the dilation, it stays there. |
| Q=B''' | This is how the scale factor of the dilation was chosen. |
| S=D''' | Since translations and rotations are rigid motions, AB=A''B'' and AD=A''D''. It is assumed that PQ/AB=PS/AD, so the dilation that moves B'' to Q, also moves D'' to S. |
| C''' is on QR | It is assumed that ∠ B≅ ∠ Q. Since rigid motions and dilations preserve angles, this means that ∠ B'''≅ ∠ Q. |
| C''' is on SR | It is assumed that ∠ D≅ ∠ S. Since rigid motions and dilations preserve angles, this means that ∠ D'''≅ ∠ S. |
| R=C''' | Both R and C''' is the intersection of QR and SR. |
The steps above give a similarity transformation that maps ABCD to PQRS, so these two quadrilaterals are similar. This proves the converse statement.