The given proportion can be rearranged to get the proportionality of two sides of
△ABC and
△DEC.
DCAD=ECBE
DCAD+1=ECBE+1
DCAD+DCDC=ECBE+ECEC
DCAD+DC=ECBE+EC
Segment Addition Postulate
DCAC=ECBC
This means that
△ABC is a dilation of
△DEC from point
C with scale factor
r=DCAC=ECBC.
A a segment to a parallel segment, so the proof is complete.
If DCAD=ECBE, then DE∥AB.