{{ item.displayTitle }}

No history yet!

Student

Teacher

{{ item.displayTitle }}

{{ item.subject.displayTitle }}

{{ searchError }}

{{ courseTrack.displayTitle }} {{ statistics.percent }}% Sign in to view progress

{{ printedBook.courseTrack.name }} {{ printedBook.name }} We want to identify the vertex and the axis of symmetry of the graph of given quadratic function. To do so, we will first express it in vertex form where $a,$ $h,$ and $k$ are either positive or negative numbers. $f(x)=-6(x+4)_{2}−3⇔f(x)=-6(x−(-4))_{2}+(-3) $
It is important to note that we do **not** need to graph the parabola to identify the desired information. Let's compare the general formula for the vertex form with our equation.
$General formula:f(x)=Equation:f(x)= -a(x−-(h()_{2}+--k-6(x−(-4))_{2}+(-3) $
We can see that $a=-6,$ $h=-4,$ and $k=-3.$

The vertex of a quadratic function written in vertex form is the point $(h,k).$ For this exercise, we have $h=-4$ and $k=-3.$ Therefore, the vertex of the given equation is $(-4,-3).$

The axis of symmetry of a quadratic function written in vertex form is the vertical line with equation $x=h.$ As we have already noticed, for our function, this is $h=-4.$ Thus, the axis of symmetry is the line $x=-4.$