Houghton Mifflin Harcourt Algebra 1, 2015
HM
Houghton Mifflin Harcourt Algebra 1, 2015 View details
4. Normal Distributions
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Exercise 5 Page 342

To start, find the difference between the mean score and the given score.

16 %

Practice makes perfect

We have been told that the scores on a test are normally distributed with a mean of 74 and a standard deviation of 8. We will find the probability that a randomly chosen junior has a score above 82. x≥ 82 First, let's find the difference between 82 and the mean. 82- 74= 8 Then, we will divide the difference by the standard deviation 8. 8/8=1 Thus, 82 is 1 standard deviation above the mean. To find the probability of choosing a junior with a score above 82, we will shade the percentage of data which is no less than 1 standard deviation above the mean.

Finally, we can find the probability of choosing a junior who has a score above 82 by adding the probabilities of the shaded areas.

p=13.5 %+2.35 %+0.15 %
p=16 %

The probability is 16 %.