body{margin:0;} noscript{z-index: 10000; position: fixed; display: block; height: 100%; width: 100%; background: #fff;} noscript .fa{font-size: 40px; display:block; color: #daa520;} noscript div{margin-top: 6%; padding-left: 20px; padding-right: 20px; text-align: center;} ! You must have JavaScript enabled to use this site.

Houghton Mifflin Harcourt Algebra 1, 2015

HM

Houghton Mifflin Harcourt Algebra 1, 2015 View details

1. Measures of Center and Spread

Continue to next subchapter

Exercise 5 Page 312

To find the median, make sure the numbers are in numerical order.

Mean: $522.088≈$522.09
Median: $427.23

Practice makes perfect

We are given the average yearly gold price for years 2000-2009. Let's find the mean and the median of these prices.

Mean

In order to find the mean, or average, we need to find the sum of the prices and divide by the number of tests.

Mean=Sum of values/Number of values

SubstituteValues

Substitute values

Mean=279.11+271.04+309.73+363.38+409.72+444.74+603.46+695.39+871.96+972.35/10

Add terms

Mean=5220.88/10

Calculate quotient

Mean=522.088

Round to 2 decimal place(s)

Mean≈ 522.09

The mean of the prices is $522.088 or $522.09.

Median

The median of a set of data is the middle number, or the average of the two middle numbers, when placed in order from least to greatest. Let's start by writing the numbers in numerical order. 271.04, 279.11, 309.73, 363.38, 409.72 | 444.74, 603.46, 695.39, 871.96, 972.35 Since there is an even number of scores, we will need to find the average of the two middle numbers, $409.72 and $444.74.

409.72+444.74/2

Add terms

854.46/2

Calculate quotient

427.23

The median price is $427.23.

Subchapter links

Explore p.305-311

Elaborate p.311

Evaluate: Homework and Practice p.312-314

Lesson Performance Task