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Houghton Mifflin Harcourt Algebra 1, 2015

HM

Houghton Mifflin Harcourt Algebra 1, 2015 View details

Module 7 Assessment Readiness

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Exercise 1 Page 268

a In order to tell whether the graph of each equation includes the given point (-6,3), we will substitute the point into the equations. If it satisfies the equation, we can say that the point is included in the graph. Let's substitute the point into the first equation.

y=-2x-6

x= -6, y= 3

3? =-2( -6)-6

MultNegNegOnePar

- a(- b)=a* b

3? =12-6

Subtract term

3≠6

Since the point does not satisfy the equation, it is not included in the graph.

b The second equation is the following.

y+3=2(x+9) Let's check whether the point (-6,3) satisfies this equation.

y+3=2(x+9)

x= -6, y= 3

3+3? =2( -6+9)

Add terms

6? =2(3)

Multiply

6=6

Since the point satisfies the equation, it is included in the graph.

c The last equation is given below.

y-4=1/2(x+4) We will check the point (-6,3) in the same way as before.

y-4=1/2(x+4)

x= -6, y= 3

3-4? =1/2( -6+4)

Add and subtract terms

-1? =1/2 (-2)

a(- b)=- a * b

-1? =-1/2*2

FracMultDenomToNumber

a/2* 2 = a

-1=-1

As a result, the point is included in the graph of the equation.

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Exercises p.268