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| Feature | f(x) | g(x) |
|---|---|---|
| Domain | -1 ≤ x ≤ 3 | -1 ≤ x ≤ 3 |
| Range | -7 ≤ f(x) ≤ 5 | -4 ≤ g(x) ≤ 4 |
| Feature | f(x) | g(x) |
|---|---|---|
| Slope | 3 | 2 |
| y-intercept | -4 | -2 |
We are told to assume that the domain of f(x) includes all real numbers between the least and the greatest values shown in the table. Since the least value of x is -1 and the greatest is 3, the domain of f(x) is:
-1 ≤ x ≤ 3.
We can determine the domain and range of g(x) by looking at the graph. The function starts at x=-1 and ends at x=3. Thus, the domain is all real numbers of x such that -1 ≤ x ≤ 3. Once again, the range is the corresponding output values. We have to look at the y-axis to identify the range. We can tell that g(x) starts at g(x)=-4 and ends at g(x)=4. Thus, the range of g(x) is: -4 ≤ g(x) ≤ 4.
Let's compare them!
| Feature | f(x) | g(x) |
|---|---|---|
| Domain | -1 ≤ x ≤ 3 | -1 ≤ x ≤ 3 |
| Range | -7 ≤ f(x) ≤ 5 | -4 ≤ g(x) ≤ 4 |
The functions have the same domains! However, the range of f(x) is different than the range of g(x).
We know that f(x) is a linear function, so we can write it in the slope-intercept form. Let's take two points from the table to find the slope using the Slope Formula! Let's use (-1,-7) and (0, -4).
Substitute ( -1,-7) & ( 0,-4)
a-(- b)=a+b
Add terms
a/1=a
Looking at the graph of g(x), we can tell that it passes through the points (-1,-4) and (3,4). Let's substitute them in the Slope Formula to find the slope!
Substitute ( -1,-4) & ( 3,4)
a-(- b)=a+b
Add terms
Calculate quotient
The slope is 2. From the graph, we can also see that the function intercepts the y-axis at y=-2. Therefore, b=-2, and we can write the final equation for g(x) as g(x)=2x-2.
Using the rules for the functions, we summarize their key features in the table below.
| Feature | f(x) | g(x) |
|---|---|---|
| Slope | 3 | 2 |
| y-intercept | -4 | -2 |