Exercise 6 Page 190

Substitute 0 for each of the variables and then solve the equation for the other variable.

x-intercept: 0
y-intercept: 0

Practice makes perfect

To determine the x-intercept for the given equation, we will substitute 0 for y and solve for x. To determine the y-intercept, we will substitute 0 for x and solve for y.

Finding the x-intercept

Think of the point where the graph of an equation crosses the x-axis. The y-value of that (x,y) coordinate pair is equal to 0, and the x-value is the x-intercept. Consider the given equation. 5x-2y=0As we have already said, let's substitute 0 for y and solve for x.

5x-2y=0

Substitute

y= 0

5x-2( 0)=0

ZeroPropMult

Zero Property of Multiplication

5x=0

DivEqn

.LHS /5.=.RHS /5.

x=0

The x-intercept of the equation is 0.

Finding the y-intercept

In the same way as above, now consider the point where the graph of the equation crosses the y-axis. The x-value of the (x,y) coordinate pair at the y-intercept is 0. Therefore, substituting 0 for x will give us the y-intercept.

5x-2y=0

Substitute

x= 0

5( 0)-2y=0

ZeroPropMult

Zero Property of Multiplication

-2y=0

DivEqn

.LHS /(-2).=.RHS /(-2).

y=0

As a result, 0 is the y-intercept of the equation.