Exercise 19 Page 53

We need to find who earned more during the last year. To do this, we will write algebraic expressions using the information provided. Since Paul has been working with Company B, he started with a salary of $30 000 and received an increase of $2400 each year. Let n be the number of years he has been working in the company. Paul's salary after $n$ years:30 000 + 2400 n The exercise asks us to compare the salaries when they had both been employed for 10 years. Thus, we need to substitute n=10 in our expression to find how much Paul earned in the tenth year.

Paul earned $54 000 during the last year he worked with Company B. We will proceed in a similar way to find out how much money Sharla earned. As she worked for Company C, she started with a salary of $36 000 and had a yearly increase of $2000. Sharla's salary after $n$ years:36 000 + 2000n Again we will substitute n=10 in the expression to find how much money she earned during the last year.

We can see that Sharla earned more than Paul. She had a salary of $56 000. Finally, let's find the difference to determine how much more she earned. $56 000 - $54 000 = $2000 We found that she earned $2000 more than Paul.