Houghton Mifflin Harcourt Algebra 1, 2015
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3. Solving Linear Systems by Adding or Subtracting
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Exercise 22 Page 411

Practice makes perfect
a

We will use an example to answer this question. Let's consider a system of linear equations.

2x+y+8=12 & (I) 2x+y+4=8 & (II) Note that both the x- and the y-variables have the same coefficient in both equations. Thus, in order to use the Elimination Method we will subtract Equation (II) from Equation (I).

2x+y+8=12 2x+y+4=8
2x+y+8-( 2x+y+4)=12- 8 2x+y+4=8
2x+y+8-2x-y-4=12-8 2x+y+4=8
4=4 2x+y+4=8

We arrived to a true statement. Its truthfulness does not depend on any variable. Thus, any value for x and y will satisfy the statement. Hence, there are infinitely many solutions. This means the two lines are coincidental. Note that whenever we arrive to a true statement, the system has infinitely many solutions.

b

To answer this question, we will consider another example.

2x+y=8 & (I) - 2x+2y=- 8 & (II) This time the x-variable has opposite coefficients. Thus, we will add the equations to eliminate it.

2x+y=8 - 2x+2y=- 8
2x+y=8 - 2x+2y+( 2x+y)=- 8+ 8
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(II): Solve for y
2x+y=8 - 2x+2y+2x+y=- 8+8
2x+y=8 3y=0
2x+y=8 y=0

We found that y=0. To find the value of the x-variable, we will substitute 0 for y in Equation (I).

2x+y=8 y=0
2x+ 0=8 y=0
2x=8 y=0
x=4 y=0

W found that the solution of the system, which is the point of intersection of the lines, is (4,0). Therefore, there is only one solution. Note that whenever we arrive to a concrete solution for each of the variables, the system has one solution.

c

Finally, to answer this question, we will use a third example.

x-y=4 & (I) x-y=0 & (II) Note that the x- and the y-variables have the same coefficient in both equations. Therefore, to solve the system, we will subtract Equation (II) from Equation (I).

x-y=4 x-y=0
x-y-( x-y)=4- 0 x-y=0
x-y-x+y=4-0 x-y=0
0=4 x-y=0

Since we know that 0≠ 4, we have arrived to a false statement. There are no values for x or y that satisfy it. Thus, the system has no solution. This means the lines do not intersect. Every time we arrive to a false statement, the system has no solution.