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Make a table of values to determine the residuals.
Sum for y=2x+3: 49
Sum for y=2.4x+3: 45
Better Line of Fit: y=2.4x+3
We have been given the following table.
| x | 1 | 2 | 3 | 4 |
|---|---|---|---|---|
| y | 4 | 11 | 5 | 15 |
We have also been given two possible lines of fit.
| Lines of Fit | |
|---|---|
| y=2x+3 | y=2.4x+3 |
In order to determine which line of fit is better, let's calculate the residuals for both lines.
| x | y (Actual) | y Predicted by y=2x+3 | Residual for y=2x+3 | y Predicted by y=2.4x+3 | Residual for y=2.4x+3 |
|---|---|---|---|---|---|
| 1 | 4 | y=2( 1)+3= 5 | 4- 5= -1 | y=2.4( 1)+3= 5.4 | 4- 5.4= -1.4 |
| 2 | 11 | y=2( 2)+3= 7 | 11- 7= 4 | y=2.4( 2)+3= 7.8 | 11- 7.8= 3.2 |
| 3 | 5 | y=2( 3)+3= 9 | 5- 9= -4 | y=2.4( 3)+3= 10.2 | 5- 10.2= -5.2 |
| 4 | 15 | y=2( 4)+3= 11 | 15- 11= 4 | y=2.4( 4)+3= 12.6 | 15- 12.6= 2.4 |
Now, we will square the residuals and find their sum s for each line so that we can compare which line is a better fit. Let's start with the line y=2x+3.
Thus, the sum of the squared residuals for y=2x+3 is 49. Next, we will continue with the line y=2.4x+3.
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The sum of the squared residuals for y=2.4x+3 is 45. As a result, we can say that y=2.4x+3 is the better line of fit because it has a lesser sum.