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Make a table of values to determine the residuals.
Sum for y=x+4: 7
Sum for y=x+4.2: 7.56
Better Line of Fit: y=x+4
We are given the following table.
| x | 1 | 2 | 3 | 4 |
|---|---|---|---|---|
| y | 4 | 7 | 8 | 6 |
We are also given two possible lines of fit.
| Lines of Fit | |
|---|---|
| y=x+4 | y=x+4.2 |
We can calculate the predicted values for y=x+4.
| x | y (Actual) | y Predicted by y=x+4 |
|---|---|---|
| 1 | 4 | y= 1+4= 5 |
| 2 | 7 | y= 2+4= 6 |
| 3 | 8 | y= 3+4= 7 |
| 4 | 6 | y= 4+4= 8 |
Now we can calculate the residuals which are the differences between the actual values and the predicted values.
| x | y (Actual) | y Predicted by y=x+4 | Residual for y=x+4 |
|---|---|---|---|
| 1 | 4 | y= 1+4= 5 | 4- 5= -1 |
| 2 | 7 | y= 2+4= 6 | 7- 6= 1 |
| 3 | 8 | y= 3+4= 7 | 8- 7= 1 |
| 4 | 6 | y= 4+4= 8 | 6- 8= -2 |
Now, we will square the residuals and find their sum s. This sum will represent how good the fit is. The lower the sum, the better fit. Let's do it!
We found that the sum for y=x+4 is s=7. Let's repeat this process for y=x+4.2.
Let's find the predicted values and the residuals for y=x+4.2.
| x | y (Actual) | y Predicted by y=x+4.2 | Residual for y=x+4.2 |
|---|---|---|---|
| 1 | 4 | y= 1+4.2= 5.2 | 4- 5.2= -1.2 |
| 2 | 7 | y= 2+4.2= 6.2 | 7- 6.2= 0.8 |
| 3 | 8 | y= 3+4.2= 7.2 | 8- 7.2= 0.8 |
| 4 | 6 | y= 4+4.2= 8.2 | 6- 8.2= -2.2 |
Now, we will square the residuals and find the sum s for the line y=x+4.2.
Calculate power
Add terms
We found that the sum s for y=4.2 is equal to 7.56.
We found that the sum of the squared residuals for y=x+4.2 is 7.56 and that the sum for y=x+4 is 7. As a result, we can say that y=x+4 is the better line of fit because it has lesser sum.