Houghton Mifflin Harcourt Algebra 1, 2015
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Houghton Mifflin Harcourt Algebra 1, 2015 View details
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Exercise 3 Page 33

Write an equation to solve for the unknown value.

Equation: 23=2w+6
Solution: $8.50

Practice makes perfect

In this exercise, the hourly pay at a new job relates to the hourly pay at an internship. The new pay is given, and we need to use it to determine the amount of money earned per hour at the internship. We can rewrite the given information as algebraic expressions to create an equation for the internship wage.

Given Information Algebraic Expression
hourly pay of the internship w
twice the hourly pay of the internship 2w
A student's pay of $23 an hour at a new job is $6 more than twice the hourly pay of the internship 23= 2w+ 6

Now that we have the equation, we can solve it for w, the hourly pay of the internship.

23=2w+6
23-6=2w+6-6
17=2w
17/2= 2w/2
8.5=w
w=8.5

Therefore, the student earned $8.50 per hour at their internship.