We want to use the to find the of the line that passes through the given points.
$\begin{gathered}
m = \dfrac{y_2-y_1}{x_2-x_1}
\end{gathered}$
In the above formula, $m$ represents the slope, and $(x_1,y_1)$ and $(x_2,y_2)$ two points on the line.

### Calculating Slope

In this exercise, we are given the points $(\text{-}3,\text{-}1)$ and $(5,\text{-}1).$ Note that, when substituting these values into the slope formula, it doesn't matter which point we choose to use as $({\color{#0000FF}{x_1}},{\color{#0000FF}{y_1}})$ or $({\color{#009600}{x_2}},{\color{#009600}{y_2}}).$ $\begin{gathered}
m=\dfrac{{\color{#009600}{1}}-{\color{#0000FF}{1}}}{{\color{#009600}{5}}-({\color{#0000FF}{\text{-}3}})} \quad \text{or} \quad m=\dfrac{\phantom{\text{-}}{\color{#009600}{1}}-{\color{#0000FF}{1}}}{{\color{#009600}{\text{-}3}}-{\color{#0000FF}{5}}}
\end{gathered}$
Both will give the same result. Here we will use the points in the given order and solve for the slope $m.$
$m = \dfrac{y_2-y_1}{x_2-x_1}$

$m=\dfrac{{\color{#009600}{1}}-{\color{#0000FF}{1}}}{{\color{#009600}{5}}-({\color{#0000FF}{\text{-}3}})}$

$m=\dfrac{0}{8}$

$m=0$

The slope of the line that passes through the given points is $0.$ This means that as $x$ increases, $y$ neither increases nor decreases. Therefore, we have a . ### Check by Graphing

Finally, let's plot the given points and connect them with a line to check if the direction of the slope matches what we calculated above.

Observing the graph, we can confirm that as $x$ moves in the positive direction, $y$ does not move in the positive or negative direction.