Graphing Horizontal and Vertical Lines

a

Equations given as only a constant $y$ -value represent a horizontal line. Thus, the $y$ -value will be $7$ for all points on the line. Let's graph three arbitrary points with $y$ -value $7 .$

We know now complete the graph with a line through the points.

b

Once again, there is no

x

in the equation which means that

x

can take all values and

y

will always be

- \frac{2}{3} .

Therefore, we should plot some points with the

y

-value

- \frac{2}{3} .

It's a bit tricky to locate

- \frac{2}{3}

but it will be somewhere between

0

and

- 1

on the

y

-axis, closer to

- 1 .

Now, the graph of $y = - \frac{2}{3}$ will pass through all points with $y$ -value $- \frac{2}{3} .$

Graphing Horizontal and Vertical Lines 1.2 - Solution