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Remember the definition of a two-way table.
See solution.
We asked 25 classmates the following.
Here is a two-way table of the results. We want to interpret them.
Curfew | No Curfew | |
---|---|---|
Chores | 13 | 4 |
No Chores | 2 | 6 |
To interpret data in a two-way table, we usually find and then compare the relative frequencies. To do so, first we need to find the totals in each row and each column. This means adding the values in each row and column. Let's do it!
Curfew | No Curfew | Total | |
---|---|---|---|
Chores | 13 | 4 | 13+4=17 |
No Chores | 2 | 6 | 2+6=8 |
Total | 13+2=15 | 4+6=10 | 25 |
Now, we can find the frequencies by row or by column. Looking at it by column, we will write the ratios of each value to the total in that column. We will then calculate the quotients. Take note that there are 15 students with curfew and 10 students without a curfew.
Curfew | No Curfew | Total | |
---|---|---|---|
Chores | 13; 1513≈0.87 | 4; 104=0.4 | 17 |
No Chores | 2; 152≈0.13 | 6; 106=0.6 | 8 |
Total | 15 | 10 | 25 |
As we divide each response of 'chores' and 'no chores' over the total number, respective of 'curfew' and 'no curfew,' we get the frequencies. Next, we need to interpret what the results mean. See that 0.87=87% of the students who have a curfew also have chores assigned. What is more, 0.13 or 13% of the students who have a curfew do not have any chores assigned.
Curfew | No Curfew | Total | |
---|---|---|---|
Chores | 13; 0.87 | 7; 0.4 | 17 |
No Chores | 2; 0.13 | 3; 0.6 | 8 |
Total | 15 | 10 | 25 |
Since 0.87>0.13, not even close, we can say that most of the students who have a curfew also have chores. For similar reasons, because 0.6>0.4, a student that does not have a curfew more likely does not have any chores assigned either. What a cool study.