Glencoe Math: Course 3, Volume 2
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Glencoe Math: Course 3, Volume 2 View details
3. Volume of Spheres
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Exercise 25 Page 611

The volume of a sphere is four thirds the product of π and the cube of the radius.

about 0.0011 grams

Practice makes perfect

We are given that a golf ball has a diameter of 42.67 millimeters.

We are asked to find the number of grams per cubic millimeter of the material used to make the ball. Let's start by calculating the volume of the ball. To do so, recall that the volume of a sphere is equal to four thirds the product of π and the cube of the radius r. V=4/3π r^3In this case, we are given the diameter of the sphere. To find the radius, we can divide the diameter d by 2.

r = d/2
r = 42.67/2
r = 21.335

We got that the radius of the sphere is 21.335 millimeters. Now we can substitute the radius into the formula and calculate the volume of the sphere.

V=4/3Ï€ r^3
V=4/3 π ( 21.335)^3
â–¼
Simplify right-hand side
V=4/3Ï€(9711.31277038)
V=4Ï€(9711.31277038)/3
V=40678.651808...
V≈ 40678.6518

The volume of the ball is about 40678.6518 cubic millimeters. We also know that the ball has a mass of 45.93 grams.Therefore, we can use a proportion to find the number of grams per cubic millimeter of the material used to make the ball. Let's write the proportion! &40678.6518mm^3/45.93gm=1mm^3/xgm Now that the proportion is written, we will solve it using cross products and then isolating x.

40678.6518/45.93=1/x
40678.6518x=45.93(1)
â–¼
Solve for x
40678.6518x=45.93
40678.6518x/40678.6518=45.93/40678.6518
40678.6518x/40678.6518=45.93/40678.6518
x=45.93/40678.6518
x=0.001129...
x≈ 0.0011

We got that about 0.0011 grams per cubic millimeter of the material was used to make the golf ball.