Glencoe Math: Course 3, Volume 2
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Glencoe Math: Course 3, Volume 2 View details
7. Distance on the Coordinate Plane
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Exercise 7 Page 435

Use the Distance Formula.

15.9 units

Practice makes perfect
To find the distance between the given points, we can use the Distance Formula. d=sqrt(( x_2- x_1)^2+( y_2- y_1)^2) Let's substitute the given coordinates, K( 8 12, 12) and L( - 6 34, 7 12) into this formula and simplify.
d = sqrt((x_2-x_1)^2 + (y_2-y_1)^2)
d=sqrt(( - 6 34- 8 12)^2+( 7 12- 12)^2)
d=sqrt((- 6* 4+3/4-8* 2+1/2)^2+(7* 2+ 1/2-12)^2)
d=sqrt((- 6* 4+3/4-8* 2+1/2)^2+(7* 2+ 1/2-12* 4/4)^2)
d=sqrt((- 24+3/4-16+1/2)^2+(14+ 1/2-48/4)^2)
d=sqrt((- 27/4-17/2)^2+(15/2-48/4)^2)
d=sqrt((- 27/4-17/2)^2+(15/2-48/4)^2)
d=sqrt((- 27/4-17* 2/2* 2)^2+(15* 2/2* 2-48/4)^2)
d=sqrt((- 27/4-34/4)^2+(30/4-48/4)^2)
d=sqrt((- 27-34/4)^2+(30-48/4)^2)
d=sqrt((- 61/4)^2+(- 18/4)^2)
d=sqrt((- 61/4)^2+(- 18/4)^2)
d=sqrt((61/4)^2+(18/4)^2)
d=sqrt(61^2/4^2+18^2/4^2)
d=sqrt(3 721/16+324/16)
d=sqrt(3 721+324/16)
d=sqrt(4 045/16)
d=sqrt(4 045)/sqrt(16)
d=63.600314 .../4
d=15.900078 ...
d=15.9
The points are about 15.9 units apart.