Glencoe Math: Course 3, Volume 2
GM
Glencoe Math: Course 3, Volume 2 View details
Chapter Review

Exercise 7 Page 443

about 79.6cm

Practice makes perfect

We are given that a kite has the shape of the following figure.

We are asked to find the width of the kite. To do so, we need to find the length of the shorter diagonal of the figure. Let's start by taking a closer look at the diagram.

Notice that the shorter diagonal consists of two equally long segments. We can see that one of the segments is a leg of a right triangle. Let's use the Pythagorean Theorem to find the second leg of the triangle. a^2+ b^2= c^2 In the formula, a and b are the lengths of the legs and c is the length of the hypotenuse of a right triangle. In our triangle, a= 25 and c= 47.

Let's substitute these values into the formula and solve for the value of b.

a^2+b^2=c^2
25^2+ b^2= 47^2
Solve for b
625+b^2=2209
b^2=1584
sqrt(b^2)=sqrt(1584)
b=sqrt(1584)
b=39.799497...
b≈ 39.8

We got that the value of b is equal to about 39.8. Now we can calculate the length of the diagonal of the figure.

We can see that the length of the shorter diagonal is twice the length of b. 2* b = 2* 39.8 = 79.6 Therefore, the width of the kite is about 79.6 centimeters.